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The scores of students in a national level examination are normally distributed with a mean of 500 and a standard deviation of 100. If the value of the cumulative distribution of the standard normal random variable at 0.5 is 0.691, then the probability that a randomly selected student scored between 450 and 500 is
Probability Between 450 and 500 (Normal Distribution)
The exam scores are normally distributed with a mean \( \mu = 500 \) and standard deviation \( \sigma = 100 \).
Given: \( P(Z \leq 0.5) = 0.691 \)
We need to find: \( P(450 \leq X \leq 500) \)
Step 1: Convert scores to Z-scores
Use the formula:
$$ Z = \frac{X - \mu}{\sigma} $$
For \( X = 500 \):
$$ Z = \frac{500 - 500}{100} = 0 $$
For \( X = 450 \):
$$ Z = \frac{450 - 500}{100} = -0.5 $$
Step 2: Find the probability using cumulative values
We calculate:
$$ P(450 \leq X \leq 500) = P(-0.5 \leq Z \leq 0) = P(Z \leq 0) - P(Z \leq -0.5) $$
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